已知函数f(x)=logax(a>0,a≠1),若f(x1)-f(x2)=3,则f(x1²)-f(x2²)=

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已知函数f(x)=logax(a>0,a≠1),若f(x1)-f(x2)=3,则f(x1²)-f(x2²)=
已知函数f(x)=logax(a>0,a≠1),若f(x1)-f(x2)=3,则f(x1²)-f(x2²)=

已知函数f(x)=logax(a>0,a≠1),若f(x1)-f(x2)=3,则f(x1²)-f(x2²)=
f(x1)-f(x2)=logax1-logax2=loga(x1/x2)=3;
f(x1²)+f(x2²)=logax1²-logax2²=loga(x1²/x2²)=2loga(x1/x2)=2×3=6;
如果本题有什么不明白可以追问,

f(x)=loga (x)
f(x1)-f(x2)=3
loga (x1)-loga(x2)=3
loga(x1/x2)=3
f(x1²)-f(x2²)=loga(x1²)-loga(x2²)
=loga(x1/x2)²
=2loga(x1/x2)
=2*3
=6

f(x1)-f(x2)=logax1-logax2=loga(x1/x2)=3
f(x1^2)-f(x2^2)=loga(x1^2/x2^2)=2*loga(x1/x2)=2*3=6