化简sin2a(1+tana*tana/2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/13 15:29:29
化简sin2a(1+tana*tana/2)
化简sin2a(1+tana*tana/2)
化简sin2a(1+tana*tana/2)
sin2a(1+tana*tana/2)
=2sinacosa[1+(sina/cosa)*(sina/2/cosa/2)]
=2sinacosa+2(sina)^2*[(sina/2)^2/(sina/2*cosa/2)]
=2sinacosa+2(sina)^2[(1-cosa)/sina)]
=2sinacosa+2sina(1-cosa)
=2sina.
令tan (a/2)=t
有cos a=cos^2 (a/2)-sin^2(a/2)=(1-t^2)/(1+t^2)
sin a=2sin (a/2)cos (a/2)=2t/(1+t^2)
tan a=2t/(1-t^2)
sin2a(1+tana*tana/2)
=4t(1-t^2)/(1+t^2)^2*(1+2t^2/(1-t^2))
=4t/(1+t^2)
=2sin a
sin2a(1+tana*tana/2)
=sin2a[(cosA*cosA/2+sinA*sinA/2)/cosA*cosA/2]
=sin2a[cos(A-A/2)/cosA*cosA/2]
=sin2AcosA/2/cosA*cosA/2
=sin2A/cosA
=2sinA
化简sin2a(1+tana*tana/2)
(sin2a+cos2a+1)/(1+tana)化简
化简(sin2A-cos2A+1)/(1-tanA)
化简tana+1/tana
1.化简[2sin2a/(1+cos2a)]*1/tana
2sin^2a+sin2a/1-tana化简
求证:1+sin2a/cos2a=1+tana/1-tana
cos2a/1+sin2a*1+tana/1-tana=?
[cos2a/(1+sin2a)]×(1+tana)/(1-tana)的值为?
[cos2a/(1+sin2a)]*[(1+tana)/(1-tana)]的值
若tana+1/tana=4,则sin2a
若tana-1/tana=4,则sin2a
求证:sin2A/2cosA(1+tan*tanA/2)=tanA
(1+tana)(1+sin2a+cos2a)-3
已知sin2a=1,求tana
tanA=2,求1/(sin2A)
为什么tanA=1-cos2A/sin2A?
sin2a等于多少TANa