数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!

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数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!
数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:
t0=0; t(n+1)=tn+(25-tn^2)/10
a) show that (tn) is convergent
b)compute the limit of tn as n goes to infinity
谢谢!

数学分析:construct a sequence (tn) of real numbers according to the following recursive rules:t0=0; t(n+1)=tn+(25-tn^2)/10a) show that (tn) is convergentb)compute the limit of tn as n goes to infinity谢谢!
a)0{tn}是有界无穷数列,所以必定收敛
b)设limtn=x,则x=x+(25-x^2)/5,x=5(x=-5舍去)
即limtn=5