#define f(a,b,x) a*x+b printf("%d,%d\n",f(3,2,1),f(6,5,f(3,2,1)));

关于定积分~错哪儿了?急~# include # define N 100# define F(x) (x)*(x)*(x)float sab(float a,float b){ float h,sum=0; scanf(%f%f,&a,&b); h=(b-a)/N; for(;a #define f(x) x*x main() {int a=6,b=2,c; C=f(a)?f(b); printf(%d ,c);} #define f(a,b,x) a*x+b #include void main() printf(%d,%d ,f(3,2,1),f(6,5,f(3,2,1))) #define f(a,b,x) a*x+b printf(%d,%d ,f(3,2,1),f(6,5,f(3,2,1))); # define A 3 # define B(a) (( A + 1 )*a ) M x = 3*( A + B( 7 ) ) ;# define A 3# define B(a) (( A + 1 )*a )Mx = 3*( A + B( 7 ) ) ;这个要怎么解答 #define F(a) #define F(x,y)x*(y) void main() {int a=3,b=4,c; c=F(a+b,(a++)+(b++));#define F(x,y)x*(y) void main() {int a=3,b=4,c; c=F(a+b,(a++)+(b++)); printf(%d/n,c);} 答案是31,求详解. #define f( a,b,x ) a*x+b原题：下列程序段的输出是 _______ .#define f(a,b,x) a*x+bprintf(%d,%dn,f(3,2,1),f(6,5,f(3,2,1)));第二个我以为是35 可为什么是25?我是这样想的：6 * f(3,2,1) + 5 = 6 * 5 + 5 = 35 #define MA（x） x*x-1 int a=1,b=2; cout #define M(x) x*x int a=3,b=2; M(a+b)/M(a+b)=? #include #define A 2 #define B(x) x*(A+2) void main() { int a=5; printf(%d ,B(a+1)); } #define A B #include #define f(x) x*x main() {int a=6,b=2,c; c=f(a)/f(b); printf(%d ,c); }为什么上面的程序输出结果为36 #include #define f(a,b,x) a*x+b void main() { printf(%d,%d ,f(3,2,1),f(6,5,f(3,2,1))); }怎么得到5,25的? #includestdio.h #define F(y) 3.84+y #define PR(a) printf(%d,(int)(a)) main(){ int x=3; PR(F(3)*#includestdio.h#define F(y) 3.84+y#define PR(a) printf(%d,(int)(a))main(){int x=3;PR(F(3)*x); }为什么结果是12啊? C语言：二分法#include#define f(x) (x*x*x-2*x*x+3*x-4)void main(){ float a=-10,b=10,c,eps=1e-5;while ((b-a)>eps){ c=(a+b)/2;if(f(c)==0) break;else if(f(a)*f(c) #define LT(a,b) ((a) )define f(x)(x*x) 和 define f(x) x*x 之间的差别.