2log底3x+log底3 2=1/2log底3 16 x为什么值

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 03:50:04

2log底3x+log底3 2=1/2log底3 16 x为什么值
2log底3x+log底3 2=1/2log底3 16 x为什么值

2log底3x+log底3 2=1/2log底3 16 x为什么值
原式为2㏒(3) x + ㏒(3) 2=1/2log(3) 16
化简:log(3) x²+log(3) 2=log(3) 4
log(3)x²+log(3) 2=2log(3) 2
log(3) x²=log(3) 2
x²=2
x=±√2

2log底3x+log底3 2=1/2log底3 16 x为什么值 log的数学题2 + log 2(为底)4= 3x-1 log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)+log(3) 已知log(2)[log(3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 log以5为底(3x-2)>log以5为底(x+1) log(2)(x)log(2)(4x)-3log(2)(x)-12=0 (log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0 log以3为底(x+1)+log以3为底(x-2)=log以3为底4方程解 log以7为底[ log以3为底(log以2为底x) ]=0,则x^1/2等于 1/log(2)x+1/log(3)x+1/log(4)x=1,x=? 已知log(2){log(3)[log(4)(x)]}=5^0,则x=? 2 log(3x)= log 4 +log(6-x)怎么求...急 log 9 X/Y=1/2(log 3 X - log 3 Y) log 9 X/Y=1/4 3log 3 X =2log 3 Y find X and Y 解关于x的方程(1)log以3为底的(log以5的x)=-1(2)2log以x为底的16-3log以16为底的x=1