In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
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In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
In one model of the hydrogen atom,the electron revolves in a circular orbit around the proton with a speed of 2.0106m/s.Determine the radius of the electron's orbit.
一个电子围绕质子做圆周运动,速度为2.0106m/s,求电子运动轨道半径.
方法就是电子和质子间的库伦力等于电子圆周运动向心力,高中水平的题,带公式算就好了.
大哥,求翻译
it is a question in university level, is not it?
try to find out the quality of proton and electron and then you can know the result
电荷力提供向心力啊 v*2/r=kxq1xq2/r*2