△ABC,求证sinA+sinB+SINc=4cosA/2*cosB/2*cosC/2

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△ABC,求证sinA+sinB+SINc=4cosA/2*cosB/2*cosC/2
△ABC,求证sinA+sinB+SINc=4cosA/2*cosB/2*cosC/2

△ABC,求证sinA+sinB+SINc=4cosA/2*cosB/2*cosC/2
sinA+sinB+sinC
=2sin((A+B)/2)cos((A-B)/2)+2sin(C/2)cos(C/2)
=2sin((π-C)/2)cos((A-B)/2)+2sin(π-(A+B)/2)cos(C/2)
=2cos(C/2)cos((A-B)/2)+2cos((A+B)/2)cos(C/2)
=2cos(C/2)(cos((A-B)/2)+cos((A+B)/2))
=2cos(C/2)2cos(A/2)cos(B/2)
=4cos(A/2)cos(B/2)cos(C/2)