∫1/(sec^2x+1)dx等于多少?

∫1/(sec^2x+1)dx等于多少? ∫secx/sec^2x-1 dx ∫1/根号x*sec^2(1-根号x)dx ∫sec^2 x / √ tan x +1 dx ∫sec²x/1+tanx dx 求积分∫(sec^2x/根号(tanx-1))dx ∫[(sec^2x-1)secx]dx= ∫ sec^2 x dx 若x=1,sec^2x,等于多少 求∫sec^2×3xdx等于多少?shihunz：∫sec^2×3x *3/3dx 中的“*3/3”怎么得来的？ ∫（sec^2x+sinx)dx 1、∫[2/(1+x^2) -sec^2)dx2、∫[√(x)+1]^2/(x) dx ∫(1+cos^3 x)sec^2 x dx 求不定积分~ ∫sec^4x dx ∫sec^2x tan^2x dx =∫dx/(2cos^2(x/2)+1)=∫sec^(x/2)dx/(2+sec^2(x/2))怎么出来的?=∫dx/(2cos^2(x/2)+1)=∫sec^(x/2)dx/(2+sec^2(x/2))求详细流程,我知识点. ∫tan^2xdx=∫(sec^2x-1)dx sec x / (1+x^2),求dy/dx忘打了--- y= （sec x) / (1+x^2) ∫ (1 + cos ^ 2 + tan ^2 ) sec^2 dx