作业帮sb help with a math problem!2x(square)-8x+7=y to calculate the minimum and maxmum value.how?i can't graph it out.
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sb help with a math problem!2x(square)-8x+7=y to calculate the minimum and maxmum value.how?i can't graph it out.
sb help with a math problem!
2x(square)-8x+7=y to calculate the minimum and maxmum value.how?i can't graph it out.
sb help with a math problem!2x(square)-8x+7=y to calculate the minimum and maxmum value.how?i can't graph it out.
∵y=2x^2-8x+7=2(x-2)^2-1
(x-2)^2≥0,
∴2(x-2)^2-1≥-1.
So,y(min)=-1
y=2x^2-8x+7
求最值而已
当x=-b/2a=2时
y有最小值-1
无最大值
Sorry i don't know either
the minimum：x=(-b)/2a=8/2*2=2
y=(4ac-b^2)/4a=[4*2*7-(-8)^2]/4*2=-1
the maxmum: x=+∞
y=+∞
应该是求最值吧，函数开口向上，所以在定义R上没有最大值，最小值在函数的顶点取到，即y(min)=(4ac-b^2)/4a=-1！
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