化简﹕|π-5|+|4-π︳+|﹣π+3.1︳请快一点=_=

化简﹕|π-5|+|4-π︳+|﹣π+3.1︳请快一点=_= 化简/π-5/+/4-π/+/-π+3.1/ 化简：|π-4|+|3-π| 算出来 化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)] 化简sin5π/4＋sin(﹣π)＋cos9π/4 化简:(sin(α-3π)*cos(-α))/(tan(α-5π)*cos^2(α-5π)*tan(4π-α)) 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简[sin(θ-5π)cot(π/2-θ)cos(8π-θ)]/[tan(3π-θ)tan(θ-3/2π)sin(-θ-4π)] sin(θ -5π)/tan(3π-θ)*cot(π/2-θ)/tan(θ -3/2π)*cos(8π-θ)/sin(-θ-4π)化简 化简（-11/6 π)+cos(12/5 π)tan（4π）-1/(cos(13π/3)) 若sin（π／2﹢α﹚＝﹣4／5,α∈﹙π／2,π﹚,则cos﹙π／3﹣α﹚＝? 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π) 化简sin(nπ+2π/3)×cos(nπ+4π/3) n属于Z 1、计算cos²π/12－1/2 2、已知tanA=2,tanB=1/3,则tan(2A＋2B) 3、化简：若α属于（3π/2,2π）,则√1﹣sin2α 4、已知cos(3π/2﹣x)=4/5 ,x属于（π,3π/2）求tan(π/4＋x)的值 5、已知sinα＋cosα＝1/2,求cos4α的值 化简sin（a-5π）cos（-π/2-a）cos（8π-a）/sin（a-3π/2）sin（-a-4π） 化简sin（a-5π）cos（-π/2-a）cos（8π-a）/sin（a-3π/2）sin（-a-4π） 化简sin(3π-α)/[sin(-α-2π)]+cos(4π-α)/[cos(α-5π)]+tan(-α)/[tan(π+α)]