S=0 i=1 sum=0 DO s=s+i i=i+1 sum=sum+s LOOP UNTIL i≥100 PRINT SUM END 是求什么的程序啊?

S=0 i=1 sum=0 DO s=s+i i=i+1 sum=sum+s LOOP UNTIL i≥100 PRINT SUM END 是求什么的程序啊? void func(char *s) { int sum = 0; while(*s) sum += (*s++ - 96); printf(%d,sum); } int main() { chvoid func(char *s) {int sum = 0;while(*s)sum += (*s++ - 96);printf(%d,sum);}int main() {char s[27];scanf(%s,s);func(s);}我想问一下这段程序 寻找程序（计算1+2!+3!+.）错误.#include #include main() { int j,i,n; do#include#includemain(){int j,i,n;double s,sum;scanf(%d,&n);sum=0;for(i=1;i SUM=1+1/2!+1/3!…+1/10!之值CLEAR sum=0 for i=1 to 10 s=1 for j=1 to i s=s*j endfor sum=sum+1/S endfor?1+1/2!+1/3!…+1/10!=,sum初学VF 问题有21：VF中的 ! 代表什么意思?2：for j=1 to i s=s*j 这句是什么意思?谢谢for j 语句S=0 i=1 Do S=S+i i=i+2 Loop while S≤200 n=i-2 Output n s=1 i=0 do while i 1、求出50到80之间之和.S=0 I=50 DO WHILE ___________① S=s+i ____________② ENDDO “ S= ” ,S if(s[i]>='0'&&s[i] 写出下列算法的时间复杂度（1）int sum(int n){for(s=0,i=1;i i=1;a=0;s=1; do{a=a+s*i;s=-s;i++;}while(i 下面程序段运行结果是 i=1; a=0; s=1; do{a=a+s*I; s=-s; i++;}while(i int i=1,s=3; do{ s+=i++; if(s%7==0) continue; else++i;} while(s 语句S=0 i=1 Do S=S+i Loop while S≤200 n=i-2 Output n int i=0,sum=1; do{sum+=i++;} while(i int i=1,s=0; do{if(!(i%2))continue;s+=i}while(++i s=0 i=2 do while i var a,i,s:longint; begin readln(a); s:=0; for i:=1 to a do s:=s+i; writeln(s); end.vara,i,s:longint;beginreadln(a);s:=0;for i:=1 to a dos:=s+i;writeln(s);end. int i=1,s=0;do { s+=i;i++};while(i<=5); printf("%d ",s);求解释,