已知a+b=2,求a3+6ab+b3

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已知a+b=2,求a3+6ab+b3
已知a+b=2,求a3+6ab+b3

已知a+b=2,求a3+6ab+b3
a3+6ab+b3=a3+b3+3ab(a+b)=(a+b)3=8
楼上的也太复杂了吧.

a+b=2
a3+6ab+b3
=(a+b)(a²-ab+b²)+6ab
=2×[(a²+2ab+b²)-3ab]+6ab
=2(a+b)²-6ab+6ab
=2(a+b)²
=2×2²
=8

a³+6ab+b³=(a+b)(a²-ab+b²)+6ab=2a²-2ab+2b²+6ab=2a²+4ab+2b²=2(a+b)²=8

解:a^3+6ab+b^3=a^3+b^3+6ab=(a+b)(a^2-ab+b^2)+6ab=2a^2-2ab+2b^2+6ab=2(a^2+2ab+b^2)=2(a+b)^2=2×2^2=8

a+b=2
(a+b)²=4
a³+6ab+b³
=(a³+b³)+6ab
=(a+b)(a²-ab+b²)+6ab
=(a+b)(a²+2ab+b²-3ab)+6ab
=(a+b)[(a+b)²-3ab]+6ab
=2×(4-3ab)+6ab
=8-6ab+6ab
=8

a³+b³+6ab=﹙a+b﹚﹙a²+b²-ab﹚+6ab=2[﹙a+b﹚²-3ab]+6ab=2﹙4-3ab﹚+6ab=8