将下列各式化简为Asin(a+β)A>0sina-根号3cosa

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/04 19:40:08

将下列各式化简为Asin(a+β)A>0sina-根号3cosa
将下列各式化简为Asin(a+β)A>0
sina-根号3cosa

将下列各式化简为Asin(a+β)A>0sina-根号3cosa
sina-√3cosa
=2(1/2*sina-√3/2*cosa)
=2(cosπ/3sina-sinπ/3cosa)
=2sin(a-π/3)