(3)等比数列{an}的前n项和为Sn,已知S3 = a2 +10a1 ,a5 = 9,则a1= ( )

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(3)等比数列{an}的前n项和为Sn,已知S3 = a2 +10a1 ,a5 = 9,则a1= ( )
(3)等比数列{an}的前n项和为Sn,已知S3 = a2 +10a1 ,a5 = 9,则a1= ( )

(3)等比数列{an}的前n项和为Sn,已知S3 = a2 +10a1 ,a5 = 9,则a1= ( )
等比数列
s3=a1q+10a1=a1(1-q^3)/1-q
q+10=1+q+q^2
q^2=9
a5=a1q^4=9
所以a1=1/9