等差数列前n项和为Sn=1/2(An+1/An),求通项An

等差数列前n项和为Sn=1/2(An+1/An),求通项An 等差数列{an}前n项和为sn,求证S2n-1=(2n-1)an (1)已知数列an的前n项和为sn满足sn=an²+bn,求证an是等差数列(2)已知等差数列an的前n项和为sn,求证数列sn/n也成等差数列 等差数列前n项和为Sn,求证:S2n-1=(2n-1)an 等差数列{an}=2n+1,前n项和为Sn,求1/S1+1/S2+.+1/Sn 等差数列{an}前n项和为Sn,求证S 2n-1项=（2n-1）an 等差数列an前n项和为Sn,求证S（2n-1）=（2n-1）an 已知数列{an}的前N项和sn=n^2+n+1,an是否为等差数列? 等差数列{an}的通项公式an=1-2n,其前n项和sn,则数列{sn/n}的前11项和为? 已知等差数列{an}的前n项和为Sn,如果Sn=(an+1/2)^2(n∈N+0,bn=(-1)^n*Sn已知等差数列{an}的前n项和Sn,如果Sn=(an+1/2)^2(n∈N+0,bn=(-1)^n*Sn,试求{bn}的前n项和Tn 数列an ,a1=1,前n项和为Sn ,正整数n对应的n an Sn 成等差数列.1.证明{Sn+n+2}成等比数列,2.求{n+2/n(n+1)(1+an)}前n项和 已知数列{an}的前n项和为Sn,且满足an+2Sn*Sn-1=0,a1=1/2.求证：{1/Sn}是等差数列 已知数列{an}中,a2=2,前n项和为Sn,且Sn=n(an+1)/2证明数列{an+1-an}是等差数列 等差数列{An}中,前n项和Sn=an2+（a-1).n+(a+2),则An=为什不能用Sn-Sn-1算 等差数列an的前n项和为Sn=n^2+4n-1,则通项公式为? 关于等差数列前n项和的问题思路 例题 等差数列中{an}的前n项和为Tn,{bn}的前n项和为Sn Tn/Sn=2n/m+1 求a8/b8 ,an/bn 设数列an的前n项和为Sn,满足an+sn=An^2+Bn+1(A不等于0)an为等差数列,求(B-1)/A 已知数列{an}中,an>0其前n项和为Sn,且Sn=1/8(an+2)²,求证：数列{an}为等差数列