cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/13 15:20:40
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
=-1
注意到
cos1+cos179
=cos1+cos(180-1)
=cos1-cos1
=0
一般地,有
cosx+cos(180-x)=0
因此
cos1°+cos2°+cos3°....+cos180°
=(cos1+cos179)+(cos2+cos178)+...+(cos89+cos91)+cos90+cos180
=0+0+...+0+0+(-1)
=-1
_1
是求和吗?
cos1°+cos2°+cos3°+……+cos179°+cos180°的值是(
Cos1°+cos2°+cos3°+……cos89°=
cos1°+cos2°+cos3°.+co180°=?
cos1°+cos2°+cos3°+.+cos360°
cos1°+cos2°+cos3°+...+cos179°化简
cos1°+cos2°+cos3°+.+cos359°等于多少.
cos1°+cos2°+cos3°+……cos180°=_______谢谢大家,给出过程吧~~~~
cos1°×cos1°+cos2°×cos2°+……+cosn
求cos1+cos2+cos3+…+cos178+cos179的值
(sin1°-cos1°)(sin2°-cos2°)(sin3°-cos3°)……(sin89°-cos89°)=一定要告诉我原因啊 谢谢最后得0.
cos1°的二次方+cos2°的二次方+cos3°的二次方+……cos89°的二次方=
cos1°²+cos2°²+cos3°²+cos4°²...+cos89°²=?
cos1°+cos2°+cos3°+...+cos²89°过程和答案!速度啊 多谢!
cos1°+cos2°+cos3°+...+cos180°的值为?到底是0还是-1?
cos1°+cos2°+cos3°+...+cos180°的值为?
求cos1°+cos2°+cos3°+...+cos178°+cos179°的值(这里的数字都是度数比如1°)求cos1°+cos2°+cos3°+...+cos178°+cos179°的值
求cos1º+cos2º+cos3º+……+cos178º+cos179º的值
cos0度+cos1度+cos2度+cos3度+…cos358度+cos359度+cos360度