作业帮2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少?
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2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少?
2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少?
2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少?
2^(log4^12)-3^(log9^27)+5^(log25^1/3)
=2^(log2(根号12))-3^(log3(根号27））+5^(log5(根号1/3)
=根号12-根号27+根号(1/3)
=2根号3-3根号3+1/3*根号3
=-2/3*根号3
log4^12
=lg12/lg4
=lg12/2lg2
=(1/2)lg12/lg2
=lg√12/lg2
=log2^√12
同理log9^27=log3^√27
log25^1/3=log5^(√1/3)
所以原式=2^(log2^√12)-3^(log3^√27)+5^[log5^(√1/3)]
=√12-√27+√(1/3)
=2√3-3√3+√3/3
=(-2/3)√3
2^(log4^12)-3^(log9^27)+5^(log25^1/3)
=[4^(log4^12)]^1/2-{9^(log9^27)}^1/2+[25^(log25^1/3)]^1/2
=√12-√27+√1/3
=2√3-3√3+√3/3
=-2√3/3
计算log4(3)*log9(32)
log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(27)+log9(2)*log4(根27)
2^(log4^12)-3^(log9^27)+5^(log25^1/3)等于多少?
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计算log9(根号2)*[log4(3)+log8(3)]
计算:(log4 3+log8 3)×log9 √2=?
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log9×log4
(log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32)
2^log4底12减3^log9底27加5^log25底1/3的值
2log4 (2-根号3)+3log9(2+根号3)错了 是2^(log4 (2-根号3))+3^(log9(2+根号3))
急 求 （log3 2+log9 2）-（log4 3+log8 3）求 （log3 2+log9 2）-（log4 3+log8 3）
（1）log4 27乘以log25 8乘以log9 5 （2）（log4 3+log8 3）（log3 2+log9 2）、
2^log4(2-√3) ^2+ 3^log9(2+√3)^2如题
2^log4(√3+2)^2+3^log9(√3-2)^2=
2^(log4 (2-根号3))+3^(log9(2+根号3))=