设u=(e^xy)(cos(x+y^2)),求du

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设u=(e^xy)(cos(x+y^2)),求du
设u=(e^xy)(cos(x+y^2)),求du

设u=(e^xy)(cos(x+y^2)),求du
对x偏导du/dx=ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2)) 偏导的那个a打不出来
对y偏导du/dy=xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2y
du={ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2))}dx+{xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2y}dy 里面的小项没有整理...

du={e^(xy)[ycos(x+y^2)-sin(x+y^2)]}dx+
{e^(xy)[xcos(x+y^2)-2ysin(x+y^2)]}dy