大学数学导数如图

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大学数学导数如图
大学数学导数如图
 

大学数学导数如图
f(x) = x^2.sin(1/x) ,x≠0
= 0 ,x=0
φ'(0) exists
g(x) = φ[f(x)]
Prove :g'(0)=0
lim(x->0) f(x) = 0 = f(0)
=>f(0) cts
f'(0) = lim(h->0) (f(h) - f(0) ) / h
=lim(h->0) h^2.sin(1/h) / h
=lim(h->0) hsin(1/h)
=0
g(x) = φ[f(x)]
g'(x) =f'(x) .φ'[f(x)]
g'(0) =f'(0) .φ'[f(0)]
=f'(0) .φ'(0)
=0.φ'(0)
=0

搞错了,

弹簧3额熔

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