若复数z1=4减3i,z2=1+2i,则z1/z2=?答案为负2/5减11/5 急

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若复数z1=4减3i,z2=1+2i,则z1/z2=?答案为负2/5减11/5 急
若复数z1=4减3i,z2=1+2i,则z1/z2=?答案为负2/5减11/5 急

若复数z1=4减3i,z2=1+2i,则z1/z2=?答案为负2/5减11/5 急
z1=4减3i,z2=1+2i,
则z1/z2=(4-3i)/(1+2i)=[(4-3i)(1-2i)]/[(1+2i)(1-2i)]=(-2-11i)/5=-2/5-11i/5

z1/z2=(4-3i)/(1+2i)
=(4-3i)(1-2i)/(1+2i)(1-2i)
=(4-8i-3i+6i^2)/(1-4i^2)
=(-2-11i)/5
=-2/5-11i/5
所以答案是对的(⊙o⊙)哦

z1/z2=(4-3i)/(1+2i)=(4-3i)(1-2i)/(1+2i)(1-2i)=(4-11i+6i平方)/1-4i平方=(-2-11i)/5

z1/z2=(4-3i)/(1+2i)=(4-3i)(1-2i)/(1+2i)(1-2i)=(4-11i+6i平方)/1-4i平方=(-2-11i)/5

z1/z2=(4-3i)/(1+2i)
=(4-3i)(1-2i)/(1+2i)(1-2i)
=(4-8i-3i+6i^2)/(1-4i^2)
=(-2-11i)/5
=-2/5-11i/5
谢谢。