已知虚数z,使得z1=z/(1+z^2)和z2=z^2/(1+z)都为实数,求z我目前就记得 z^2 = z的共讹

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已知虚数z,使得z1=z/(1+z^2)和z2=z^2/(1+z)都为实数,求z我目前就记得 z^2 = z的共讹
已知虚数z,使得z1=z/(1+z^2)和z2=z^2/(1+z)都为实数,求z
我目前就记得 z^2 = z的共讹

已知虚数z,使得z1=z/(1+z^2)和z2=z^2/(1+z)都为实数,求z我目前就记得 z^2 = z的共讹
z1=z/(1+z^2)
z1+z^2*z1=z (1)
z2=z^2/(1+z)
z2+z2z=z^2
z^2代入(1)式得
z1+z1z2+(z1z2-1)z=0
z1z2-1=0
z1(z1+z2)=0
z1=z2=1
所以
z=1+z^2
z=1/2+sqrt(3)i/2

z=1/2-sqrt(3)i/2